b^2-12b+28=-7

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Solution for b^2-12b+28=-7 equation:


Simplifying
b2 + -12b + 28 = -7

Reorder the terms:
28 + -12b + b2 = -7

Solving
28 + -12b + b2 = -7

Solving for variable 'b'.

Reorder the terms:
28 + 7 + -12b + b2 = -7 + 7

Combine like terms: 28 + 7 = 35
35 + -12b + b2 = -7 + 7

Combine like terms: -7 + 7 = 0
35 + -12b + b2 = 0

Factor a trinomial.
(5 + -1b)(7 + -1b) = 0

Subproblem 1

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Subproblem 2

Set the factor '(7 + -1b)' equal to zero and attempt to solve: Simplifying 7 + -1b = 0 Solving 7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b = 0 + -7 -1b = 0 + -7 Combine like terms: 0 + -7 = -7 -1b = -7 Divide each side by '-1'. b = 7 Simplifying b = 7

Solution

b = {5, 7}

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